Z^2+(2+i)+(3+i)=0

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Solution for Z^2+(2+i)+(3+i)=0 equation:


Simplifying
Z2 + (2 + i) + (3 + i) = 0

Remove parenthesis around (2 + i)
Z2 + 2 + i + (3 + i) = 0

Remove parenthesis around (3 + i)
Z2 + 2 + i + 3 + i = 0

Reorder the terms:
2 + 3 + Z2 + i + i = 0

Combine like terms: 2 + 3 = 5
5 + Z2 + i + i = 0

Combine like terms: i + i = 2i
5 + Z2 + 2i = 0

Solving
5 + Z2 + 2i = 0

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + Z2 + -5 + 2i = 0 + -5

Reorder the terms:
5 + -5 + Z2 + 2i = 0 + -5

Combine like terms: 5 + -5 = 0
0 + Z2 + 2i = 0 + -5
Z2 + 2i = 0 + -5

Combine like terms: 0 + -5 = -5
Z2 + 2i = -5

Add '-2i' to each side of the equation.
Z2 + 2i + -2i = -5 + -2i

Combine like terms: 2i + -2i = 0
Z2 + 0 = -5 + -2i
Z2 = -5 + -2i

Simplifying
Z2 = -5 + -2i

Reorder the terms:
5 + Z2 + 2i = -5 + -2i + 5 + 2i

Reorder the terms:
5 + Z2 + 2i = -5 + 5 + -2i + 2i

Combine like terms: -5 + 5 = 0
5 + Z2 + 2i = 0 + -2i + 2i
5 + Z2 + 2i = -2i + 2i

Combine like terms: -2i + 2i = 0
5 + Z2 + 2i = 0

The solution to this equation could not be determined.

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